$vincitore = 'vincitore';
$nick = '#DTB15M';
$cittatorneo = 'Aprilia';
$que = mysql_query("SELECT
AA.*,
AA.name AS tagghete,
C.*,
B.item_id
FROM tags AA,
items_tags B,
items C
WHERE AA.name IN ('1 classificata', '$vincitore','$nick', '$cittatorneo') AND
AA.id = B.tag_id AND
C.id = B.item_id
GROUP BY B.item_id
HAVING COUNT(tag_id) = 4;
",$connection)
or die(mysql_error());
while($data = mysql_fetch_array($que))
{
?>
2015
" alt=" echo $data[name]; ?>" />
echo $data[name]; ?>